<转自77169>

把下面保存成 Test.asp
$mysql_server_name = "localhost";
$mysql_username = "root";
$mysql_password = "password";
$mysql_database = "phpzr"; //?????
$conn=mysql_connect( $mysql_server_name, $mysql_username, $mysql_password );
mysql_select_db($mysql_database,$conn);
$id=$_GET['id'];
$sql = "select username,password from admin where id=$id";
$result=mysql_db_query( $mysql_database, $sql,$conn );
$row=mysql_fetch_row($result);
?>

PHP
注入测试专用

BY:孤狐浪子 QQ:393214425

Blog: Http://itpro.blog.163.com

创建数据库代码：保存成test.sql 使用phpmyadmin执行就ok了

Create DATABASE `phpzr` ; //创建数据库名称


Create TABLE admin (
id int(10) unsigned NOT NULL auto_increment,
username char(10) NOT NULL default '',
password char(10) NOT NULL default '',
useremail char(20) NOT NULL default '',
groupid int(11) NOT NULL default '0',
PRIMARY KEY (id)
) TYPE=MyISAM;



Insert INTO admin VALUES (1, 'admin', 'itpro.blog.163.com','itpro@163.com', 1);
Insert INTO admin VALUES (2, 'admin1', 'itpro.blog.163.com','itpro@163.com', 2);
Insert INTO admin VALUES (3, 'admin2', 'itpro.blog.163.com','itpro@163.com', 3);
Insert INTO admin VALUES (4, 'admin3', 'itpro.blog.163.com','itpro@163.com', 4);
Insert INTO admin VALUES (5, 'admin4', 'itpro.blog.163.com','itpro@163.com', 5);

Create TABLE admin1 (
id int(10) unsigned NOT NULL auto_increment,
username char(10) NOT NULL default '',
password char(10) NOT NULL default '',
useremail char(20) NOT NULL default '',
groupid int(11) NOT NULL default '0',
PRIMARY KEY (id)
) TYPE=MyISAM;



Insert INTO admin1 VALUES (1, 'admin', 'itpro.blog.163.com','itpro@163.com', 1);
Insert INTO admin1 VALUES (2, 'admin1', 'itpro.blog.163.com','itpro@163.com', 2);
Insert INTO admin1 VALUES (3, 'admin2', 'itpro.blog.163.com','itpro@163.com', 3);
Insert INTO admin1 VALUES (4, 'admin3', 'itpro.blog.163.com','itpro@163.com', 4);
Insert INTO admin1 VALUES (5, 'admin4', 'itpro.blog.163.com','itpro@163.com', 5);



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